Kp Calculator (Kc ⇌ Kp Conversion)
Convert between Kc (concentration-based equilibrium constant) and Kp (pressure-based) using Kp = Kc × (RT)^Δn. Furthermore, Δn is the change in moles of gaseous species (gas product moles minus gas reactant moles), and R = 0.08206 L·atm/mol·K.
How to use the Kp Calculator (Kc ⇌ Kp Conversion)
Choose Kc → Kp or Kp → Kc. Furthermore, both directions use the same equation Kp = Kc × (RT)^Δn, just rearranged.
Type the known equilibrium constant. Furthermore, Kc uses mol/L concentrations; Kp uses atm pressures.
Δn = moles of gaseous products − moles of gaseous reactants in the balanced equation. Furthermore, pure solids, liquids, and solvents are excluded.
Required because RT varies with T. Furthermore, use Kelvin or Celsius — the calculator converts.
Kp or Kc appears alongside (RT)^Δn conversion factor. Moreover, when Δn = 0, Kp = Kc exactly.
Variants, options and when to use each
| Reaction | Δn | Kp vs Kc |
|---|---|---|
| N₂(g)+3H₂(g)⇌2NH₃(g) | -2 | Kp < Kc (Δn negative) |
| N₂O₄(g)⇌2NO₂(g) | +1 | Kp > Kc |
| H₂(g)+I₂(g)⇌2HI(g) | 0 | Kp = Kc |
| CO(g)+3H₂(g)⇌CH₄(g)+H₂O(g) | -2 | Kp < Kc |
The formula explained
Kc = concentration equilibrium constant (dimensionless, using c/c° where c° = 1 mol/L)
R = 0.08206 L·atm/mol·K (gas constant in pressure-volume units)
T = temperature (Kelvin)
Δn = (mol gaseous products) − (mol gaseous reactants)
The relationship Kp = Kc(RT)^Δn comes from PV = nRT → P = (n/V)RT = [c]RT for ideal gases. Furthermore, each gaseous species contributes a factor of RT when converting from concentration to pressure. Δn net factors of RT emerge — one for each net mole of gas formed. Moreover, when Δn = 0, no net RT factors appear and Kp = Kc exactly.
Worked example — N₂O₄ ⇌ 2NO₂ at 25°C
| Step | Calculation | Result |
|---|---|---|
| Kc at 25°C | given | 4.61 × 10⁻³ |
| Δn = 2 − 1 | mol NO₂ products − mol N₂O₄ | +1 |
| RT = 0.08206 × 298 | — | 24.45 |
| Kp = Kc × (RT)^1 | 4.61×10⁻³ × 24.45 | 0.1127 |
What are Kp and Kc in equilibrium chemistry?
Kc is the equilibrium constant expressed in terms of molar concentrations (mol/L). Kp is the equilibrium constant expressed in terms of partial pressures (atm). Furthermore, both describe the same equilibrium — they differ only in the units used to express species amounts. For reactions involving no gases or equal gas moles on both sides (Δn = 0), Kp = Kc.The conversion factor (RT)^Δn comes from the ideal gas law PV = nRT. Moreover, for a gas, concentration c = n/V = P/(RT), so P = cRT. Each gaseous species in the equilibrium expression contributes a factor of RT when converting between concentration and pressure. Moreover, Δn net factors of RT appear in Kp/Kc.
Thermodynamic equilibrium constants are formally dimensionless — concentrations are divided by a standard state (c° = 1 mol/L) and pressures by a standard state (P° = 1 atm). Additionally, this is why Kp and Kc have the same numerical value when using these dimensionless conventions — the RT conversion is built into the units.
Who uses this calculator?
Physical chemists convert between Kp and Kc when equilibrium data is available in one form but needed in another. Furthermore, gas-phase equilibria are more naturally described by Kp; aqueous equilibria by Kc. Chemical engineers designing gas-phase reactors (Haber process, SO₃ oxidation, steam reforming) use Kp with partial pressures from process conditions. Moreover, thermodynamic tables typically list Kp values for gas reactions.
Historical context and related concepts
The equilibrium constant was introduced by Guldberg and Waage (1864) in concentration form. Furthermore, the pressure form Kp and the relationship Kp = Kc(RT)^Δn were developed as kinetic theory and the ideal gas law were connected to thermodynamic equilibrium in the late 19th century. Van't Hoff's equation (1884) related K to temperature, establishing the complete thermodynamic framework. Moreover, modern thermodynamics defines K in terms of dimensionless activities — unifying Kp and Kc.
Why Kp is essential for industrial gas-phase equilibrium design
Industrial gas reactions (ammonia synthesis, methanol production, Fischer-Tropsch synthesis) are designed around Kp values at specific temperatures and pressures. Furthermore, increasing pressure shifts equilibria with Δn < 0 toward products — the Haber process runs at 150–300 atm precisely because Δn = −2 for NH₃ synthesis. Moreover, Kp calculations guide the selection of operating temperature and pressure to achieve target conversion.Kp in atmospheric chemistry and ozone depletion
Atmospheric equilibria for ozone (O₃ ⇌ O₂ + O, Δn = +1), NO₂ (2NO₂ ⇌ N₂O₄, Δn = −1), and hydroxyl radical reactions are all described by Kp values at stratospheric temperatures. Furthermore, the ozone hole results from catalytic Cl reactions with Kp-governed kinetics — temperature and pressure determine both Kp and rate constants. Moreover, atmospheric models require precise Kp values to simulate photochemical smog and climate chemistry.
Frequently asked questions
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