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📏 Distance & Midpoint Calculator

From (−2, 1) to (4, 5): distance = 2√13 exactly — the simplified radical form homework requires — with the decimal alongside, and the midpoint (1, 3).

Point 1: (,)  Point 2: (,)

Coordinates accept integers, decimals and fractions (1/2).

d = 2√13

distance (exact, ≈ 7.211103)

(1, 3)

midpoint (exact)

Working

  1. Differences: Δx = 4 − -2 = 6, Δy = 5 − 1 = 4
  2. Pythagoras: d² = Δx² + Δy² = 36 + 16 = 52
  3. Take the root and simplify: d = √52 = 2√13 (simplified radical form — the form homework answers expect)
  4. Midpoint = averages of the coordinates: ((x₁+x₂)/2, (y₁+y₂)/2) = (1, 3)

Distance comes out in simplified radical form — 2√13, not 7.2111 — with the decimal alongside. Runs locally.

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How the distance & midpoint calculator works

The distance formula is Pythagoras in coordinates: d = √(Δx² + Δy²). The tool computes Δx and Δy as exact rationals, squares and sums them exactly, then simplifies the square root symbolically — extracting square factors so √52 becomes 2√13 — and only then offers a decimal approximation alongside. The midpoint is the coordinate-wise average ((x₁+x₂)/2, (y₁+y₂)/2), kept as exact fractions. Every step of the working is shown: the differences, the squares, the sum, the simplification.

The simplified radical answer is the genuinely rare feature: most online distance calculators jump straight to 7.2111, but "give your answer in simplified radical form" is how the question is actually asked in algebra and geometry courses — and 2√13 is the answer that scores. It also chains: the next line of many problems needs d², which is exact only if d stayed symbolic.

Frequently asked questions

What is the distance formula?

d = √((x₂ − x₁)² + (y₂ − y₁)²) — the Pythagorean theorem applied to the right triangle formed by the two points. From (−2, 1) to (4, 5): d = √(6² + 4²) = √52 = 2√13.

Why give the answer as a radical instead of a decimal?

Because 2√13 is exact and 7.2111 is not — and algebra/geometry courses explicitly ask for "simplified radical form". The tool gives both, exact first.

How is the radical simplified?

By extracting square factors: 52 = 4 × 13, so √52 = 2√13. The tool factorizes the sum of squares and pulls out every square factor automatically.

What is the midpoint formula?

The average of the coordinates: M = ((x₁+x₂)/2, (y₁+y₂)/2). It's the point exactly halfway along the segment — computed here as exact fractions, so the midpoint of (0,0) and (1,1) is (1/2, 1/2), not (0.5, 0.5) pretending to be exact.

Do fractional or decimal coordinates work?

Yes — coordinates parse as exact rationals, and the radical simplification handles the resulting fractions correctly (√(p/q) is rationalized to a clean coefficient times a square-free root).

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